Applying Count/Distinct Count operation on Dimension

Hello there,

I am having little trouble finding a data operation which can reflect my dimensional values in form of count or lets say numbers,

For example, I have two Columns like ,

Dimension	Measure
Bldg1	10
Bldg2	20
Bldg3	50
Bldg4	70

What i want to get is Total Sum of Measures / Total Count of Dimensions and average it out, 150/4 = 37.5

how can i do this on Board, help requested

Note: Dimension is in Entity, Measure is in Cube

Thanks & Regards,

Malav

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Alexander Kappes

Dear Malav Shelat,

the best solution for you depends to your case.

When you just want to display, you can use the DownTotal from our DataView Object. In general we also have some further options, which can be used for the totals.

For the case you want to calculate with this Total, we have the commands (dt, gt, rt) which can be used in Column Algorithm. Some more details you can find here. (Column Algorithm )

Hope it helps.

regards

Alexander Kappes

Previous Member

Hello Alexander Kappes ,

Dimension Column is an entity , i am aware of the above solution you gave, what i am looking for is Count/distinct Count of an entity column, For example,

lets say i have Customers Column as an entity(Dimensional Value)

and SalesAmount in Cube (Measure )

now what shall i do if i want to find what numbers of Customers has produced 'X' sales amount , for that i need to count the number of Customers, which i am not able to do rightnow.

Did i put that right ?

looking for further help,

Thanks

Alexander Kappes

Dear Malav Shelat,

you can do the following. You insert a column algorithm just with the value 1 inside your layout. Now for each row, you see the value 1 and can also build a total about this.

In general you can also think about using MXC Cubes, which are special counter cubes can be used directly by dataloading from source system. MXC data type

Hope this helps.

regards

Alexander Kappes

Previous Member

Yes Alexander Kappes,

MXC will be the correct process to follow on this because if i insert value 1 using algorithm in the layout then i will not be able to get distinct count,

Thank you so much for your help Alexander,

Thanks and Regards,

Malav