Label subtitution formulas to view a layout selection on a specific entity

Daniele Di Lorenzo · 2024-02-14T08:21:56+00:00

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Daniele Di Lorenzo

Hello

using substitution formulas I can highlight in a label the selection for a specific entity.

e.g. @Year returns the selected year.

But, as far as I understand, if I want to show a layout selection I can only use

@Selection_Ex(Layout="Layout_Title")

without the capability to choose one entity

Is there any way to obtain this? thanks

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Samson Sunny

Hi @Daniele Di Lorenzo,

You can add the parameter- Entity= " " along with the layout title parameter to the substitution formula to view the layout selection on a specific entity.

FORMULA SYNTAX: @Selection_Ex(Layout="Layout_Title",Entity="Entity_Name")

For example: @Selection_Ex(Layout="DV1",Entity="SKU")

The above should return only the layout selection on the Entity "SKU" for the layout "DV1" even though there are layout selections on other entities.

Daniele Di Lorenzo

thank you

I tested this syntax but is not working

with @Selection_Ex(Layout="FY_TOT") it returns the layout selection indicating the entity with active selection. But I don't want to see it, I want to see the related year.

Typing @Selection_Ex(Layout="FY_TOT", Entity="Year") it's not resolved.

Anyway, in the meantine I find this workaround: I set a layout in the label with same layout select and set a block to see the year involved.

thanks!

Samson Sunny

Hi Daniele,

Thanks for the workaround.

You might be aware of this but just wanted to point out that the @Selection_Ex(Layout="FY_TOT", Entity="Year") will work only if you have the time entity "Year" selected in the layout. It won't work when you have the selection on the other time entities other than year.

Daniele Di Lorenzo

ok, clear

yes, this is the reason

thanks!